Given that f(x) = x2 + 3x + 6 and g(x) = the quantity of x minus three, over two , solve for f(g(x)) when x = 1. (1 point)?

We want to evaluate f(g(1))

So g(x) = (x - 3)/2   

when x =1

g(1) = (1 - 3) /2 = -2/2 = -1

So

f(g(1)) = f(-1) = (-1)² + 3(-1) + 6 =  1 - 3 + 6 = 4

the answer is

4

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.