Solve the system of equations using substitution. 3y = –1/2x + 2 y = –x + 9

For the given equations, (x,y)=(10,−1)

[1]3y=−12x+2
[2]y=−x+9

While it is not technically necessary, I find it easier to clear the fractions before actually beginning; so multiplying [1] by 2
[3]6y=−x+4

Substituting (from [2]) (−x+9) for y in [3]
[4]6(−x+9)=−x+4

Simplifying
[5]−6x+54=−x+4
[6]5x=50
[7]=10

Substituting (from [7]) 10 for x in [2]
[8]y=−10+9=−1

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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