An expression is shown below: f(x) = −16x2 + 24x + 16 part a: what are the x-intercepts of the graph of f(x)? show your work. (2 points) part b: is the vertex of the graph of f(x) going to be a maximum or minimum? what are the coordinates of the vertex? justify your answers and show your work. (3 points) part c: what are the steps you would use to graph f(x)? justify that you can use the answers obtained in part a and part b to draw the graph. (5 points)

A-16x^2 + 24x + 16 = 0-8(2x^2 - 3x - 2) = 0-8(2x + 1)(x - 2) = 0(2x + 1 = 0 or x - 2 = 0x = -0.5 , 2the x-intercepts are -0.5 and 2.b. as the coefficient of x^2 ( = -16) is negative the vertex of the graph will be a maximumconverting to vertex form: -f(x) =  -8(2x^2 - 3x - 2)f(x) = -16 ( x^2 - 1.5x)  + 16      =    -16[ (x - 0.75)^2 - 0.5625) + 16      = -16(x - 0.75)^2 + 9 + 16      = -16(x - 0.75)^2 + 25so the vertex is at (0.75, 25)c.  you can plot the zeroes at (-0.5,0) and (2,0) . the graph is a parabola that opens downwards  with a maximum at (0.75, 25) and is symmetrical  about the line x = 0.75. 

Ithink it’s b, hope this .