What is the perimeter of quadrilateral abcd? 18 + units 18 + units 18 + units 18 + units

18+√26 units

Step-by-step explanation:

We have to find the perimeter of quadrilateral ABCD

length of AD=2-(-3)

                   =5 (since, it was a straight line from (-3,-3) to (-3,2))

length of AB=4-(-3)

                   =7 (since, it was a straight line from (-3,2) to (4,2))

length of DC=3-(-3)

                   = 6 (since, it was a straight line from (-3,-3) to (3,-3))

now, length of CD=

Hence, perimeter of ABCD=5+7+6+√26

                                           = 18+√26 units

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9

you need to rotate this triangle about the origin 270 degrees clockwise to create the full square.