The base of a triangle is twelvetwelve more than twice its height. if the area of the triangle is 4545 square centimeters, find its base and height.

In order to begin we must start off with the formula for the area of a triangle, which is a=1/2b(h) where a is area, b is base, and h is height.

In this scenario, we know that the area is 45cm^2 and the base is 2h+12 (since it is twice it’s height plus twelve). We can plug this into the area equation and then proceed to solve out accordingly.
a=1/2b(h)
45=1/2(2h+12)(h)
90=(2h+12)(h)
90=2h^2 + 12h
0= 2h^2 + 12h - 90

Simplify by dividing the two out.

h^2 + 6h - 45 = 0.

Now plug into the quadratic formula (with a=1, b=6, and c=-45) as shown in the image below.

After plugging the equation in and solving, we come to the idea that h is roughly equal to 4.34. We can now plug this back into the triangle area formula to solve out for b.
a=1/2b(h)
45=1/2(2h + 12)(h)
45=1/2(20.69)(4.34)
45=45.

In conclusion;
The height is ≈ 4.34
The base is ≈ 8.68

Hope this helps :)

Skew lines(segments) are lines(segments) in 3 dimensions that do not intersect the given segment and are not parallel to it.  ae, bf, eg, and fh are your skew segments.  i hope that : )