Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15. n an 1 4 2 −12 3 36

The sum of the term 4 through term 15 is 14,348,880

Given the sequence of numbers 4, -12, 36...

The sequence is geometric in nature.

The sum of the nth term of the sequence will be given as:

For this sequence, the 4 term will serve as our "a"

a = T4 = (36 * -3) = -108

r = -12/4 = 36/-12 = -3

n = 12 (4th to 15term)

Substitute into the formula;

Hence the sum of the term 4 through term 15 is 14,348,880

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