1)circle 1 is centered at (−4, 5)(−4, 5) and has a radius of 2 centimeters. circle 2 is centered at (2, 1)(2, 1) and has a radius of 6 centimeters. what transformations can be applied to circle 1 to prove that the circles are similar? enter your answers in the boxes. the circles are similar because you can translate circle 1 using the transformation rule (, ) and then dilate it using a scale factor of . 2)the sector of a circle with a 12-inch radius has a central angle measure of 60°. what is the exact area of the sector in terms of π ?

Figures of same shape and size are similar .Two circles  C1&C2 will be similar.

Circle 1 has a center of (-4,5) and circle 2 has a center of (2,1) .The x of the center is having the translation x+6 and the y  is having a translation of y-4.The center of the circle is dilated by 3 units.

The circles are similar because you can translate Circle 1 using the transformation rule (x+6,y-4 ) and then dilate it using a scale factor of 3.

2) Area of sector = ÷360.

Where α is the angle made at center.

Area of given sector= π(12)(12)(60)÷360 =24π.

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step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl