1a. if $$f(x) = \frac{2x-8}{x^2 -2x - 3} \qquad\text{ and }\qquad g(x) = \frac{3x+9}{2x-4}$$find the sum of the values of $x$ where the vertical asymptotes of $f(g(x))$ are located. 1b. what is the horizontal asymptote as $x$ approaches negative infinity of $f(g(x))$? (don't forget that an asymptote is a line, and not a number! )

The function f(g(x)) eventually simplifies to
   f(g(x) = (4/3)(x-5)(x-2)/(x² - 6x - 7)

a) The sum of the x-coordinates of the vertical asymptotes is the opposite of the x-coefficient in the denominator: 6.

b) Since the numerator and denominator are of the same degree, the horizontal asymptote is the overall multiplier: y = 4/3.

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Consider a quadratic with roots at "a" and "b". Then the factored form is
   (x-a)(x-b)
and the expanded form is
   (x² - (a+b)x + ab)
That is, the sum of the roots is the opposite of the x-coefficient. For this problem, that sum is the sum that is requested in part A.

Many things that seem threatening in the dark become welcoming when we shine light on them

This polygon has 4 sides
180(4-2) = 180(2) = 360 degree
80+90+2x + 3x = 360
170+5x = 360
5x = 190
x= 38
measure of angle t is 2(38)= 76
the answer is c. trust me
hope this !