8) divide -2x^3 -5x^2 + 4x + 2 by x +2 a)-2x^2-x+6 b)-2x^2 - x + 6, r 14 c)-2x^2 - x + 6, r -10 d)-2x^2 - 9x+ 22, r -42 9) find the roots of the polynomial equation. x^3-2x^2 + 10x + 136=0 a)-3 plus or minus 5i, -4 b)3 plus or minus 5i, -4 c)-3 plus or minus i, -4 d)3 plus or minus i, 4

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

the reporter's right

step-by-step explanation:

1/4 = .25 / 25%