Iq scores are normally distributed with a mean of 100 and a standard deviation of 15. what percentage of people have an iq score higher than 66, to the nearest tenth?

We need to find the area under the standard normal curve that is to the right of 66.

Various ways of doing this include the following:

1) Calculator:  normalcdf(66, 10000, 100, 15) = 0.988, or 98.8%

2) z-scores (using a published table of z scores)
                                                                                      66 - 100
     a)  Find the z score corresponding to 66.  It is z = = -2.27
                                                                                             15

      b) Find the area under the st. normal curve to the left of z=-2.27 (it is                   0.012).  Subtract that area from the total area, 1.000.  The result will                be the answer to this question. 

The answer is “faster”.

Sub to pewdiepie he needs to stay #1