How do i graph, label and shade the inequality 2x+3y> 100 (50,0) (0,33)

The first step is to replace the sign > with =. The inequality will change to an equation; 2x+3y=100.
Then look for different values of x and y that will make the equation true. These points can be (50,0), (20,20), (35,10) and many others. 
Plot these points and then draw a doted line. Doted line means that the points on that line do not satisfy the inequality 2x+3y>100.

To know the point to shade, take a point on either side of the line, e.g., (0,0), and substitute it in the inequality. If the point is true for the inequality, shade the other and if it is not correct shade that side. We shade the unwanted region. 
In this case, substituting the point (0,0) we get; 2(0) + 2(0) > 100
                                                                                   0 >100
This is not true. So, shade the region with this point. 

Ibelieve the answer is b. y=0 would make the line horizontal across the x.