The moose population in a new england forest can be modeled by the function y = 60x/ 1 + 0.625x . what is the value of the horizontal asymptote? describe it's meaning in the context of the problem.  a) y = 96; the maximum number of moose that the forest can sustain at one time.    b) x = 96; the maximum number of moose that the forest can sustain at one time.  c)  x = -1.6; the minimum number of moose that the forest can sustain at one time.  d) y = -1.6; the minimum number of moose that the forest can sustain at one time.

a.

step-by-step explanation:

step 1 distribute 2 to every term in the parentheses

step 2 add 10 on both sides of the equal sign

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;