What is the standard deviation of the following data set rounded to the nearest tenth? 51.8, 53.6, 54.7, 51.9, 49.3 a.3.4 b.3.3 c.1.9 d.1.8

51.8, 53.6, 54.7, 51.9, 49.3
the standard deviation of the data set will be found as follows:
Var=∑(x-μ)²/(n)
μ-mean
μ=(51.8+53.6+54.7+51.9+49.3)/5
μ=261.3/5=52.26
Next:
∑(x-μ)²=(51.8-52.26)²+(53.6-52.26)²+(54.7-52.26)²+(51.9-52.26)²+(49.3-52.26)²
∑(x-μ)²=16.852
thu
Var(x)=16.852/(5)=3.3704

Hence the standard deviation will be:
σ=√3.3704=1.835865~1.8

D] 1.8