I'm not great at probability and statistics .. the probability that a dessert sold at a certain cafe contains chocolate is 74%. the probability that a dessert contains both chocolate and nuts is 24%. find the probability that a randomly chosen chocolate dessert contains nuts. a) 17.8b) 32.4c) 31.4d) 50

Let  the probability that dessert contains chocolate be P(C)=0.74, let the probability that dessert contains nuts be P(N) and let the probability that dessert contains both be: P(N and P)=0.24
thus, the probability that randomly chosen chocolate dessert contains nuts will be given by:
P(NIP)=[P(N and C)]/P(C)
plugging in the values we obtain:
P(NIP)=0.24/0.74=0.324=32.4%

B]32.4

29. because you will divide each number of months by 12 to find the number of years. which would mean, 5, 12.5, 16, 45, 50, 72.5. which is crazy. anyhow, i think you find the median in the middle. and yea hope your test goes good

Really long apparently