11. write the equation in slope intercept form that has a slope of -23 and passes through the point (-1, 2). 12. identify the y - intercept in the equation. y = 2x -5 13. using the laws of exponents, what is (2x3y2)3?

11. y = -23x - 21

You can get this by starting with y = mx + b (slope intercept form). Then put in all the knowns and solve for the b. 

2 = -23(-1) + b
2 = 23 + b
-21 = b

Then add that to the end of the equation with m = -23

12. -5

The y-intercept of an equation is always the number added on at the end of an equation. It is also the number with no x attached to it. 

13. 8x^9y^6

When you use the law of exponents, you need to make sure the exponent goes to each individual term. When we cube the 2, it becomes 8. When you cube x^3, you get x^3*x^3*x^3 or x^9. And with y^2 you get y^6 

Ithink the answer is c just trying to others