What equation represents a parabola with a focus of (0,4) and a directrix of y=2

Any point (x,y) on the parabola is equidistant from the focus and the directrix

Therefore,

√[(x−0)²+(y−4)²]=y−(2)

√[x²+(y-4)²]=y-2

x²+(y-4)²=(y-2)²

x²+y²-8y+16=y²-4y+4

x²=4y-12> 4y=x²+12>y= (x²/4)+3

the answer is

y= (x²/4)+3

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

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step-by-step explanation: