The equation h(t) = − 16t^2 + 19t + 110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff. what is the initial velocity when the rock is thrown?

The initial velocity is 19 ft/s.

This equation is in the form
h(t) = -16t²+v₀t+h₀, where -16 is the gravitational constant, v₀ is the initial velocity, and h₀ is the initial height. 

Our equation is h(t) = -16t²+19t+110.  In this equation, the number in place of v₀ is 19, so the initial velocity is 19.

Where is your question?