Jamar rolls a 1-6 number cube three times . what is the probablility he will roll an even number, then a 6 ,then a 4?

1/48

To solve this problem, we take the probability of each step (each time he rolled) then multiply the fraction together. For the first roll, there is half a chance he will roll an even number. 
Even numbers in a standard die: 2, 4, 6
Numbers (faces) in a standard die: 1, 2, 3, 4, 5, 6
3/6 = 1/2.

For the second roll, there is 1/6 of a chance that he will roll a 6, since, there is only one face with six on it and six faces in total. 

For the third roll, there is 1/6 of a chance that he will roll a 4, since, there is only one face with four on it and six faces in total.

The last step is to multiply these results together. 1/2 * 1/6 * 1/4 = 1/48.

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