There are two sizes of red and blue marbles in a box. if the big marbles in the box, 45 are red and 3/4 are blue. the fraction of small marbles that are red is 2/5 and the fraction of small marbles that are are blue is 3/5. there are 24 more small blue marbles than small red marbles. what percent of the marbles are big marbles?

Let
x------> amount of  big marbles in the box
y------> amount of  small marbles in the box
R----> amount of  small marbles that are red in the box
B----> amount of  small marbles that are blue in the box

we know that
x=45+(3/4)*x----> x-(3/4)*x=45----> x/4=45-----> x=180

R+B=y-----> equation 1
R=(2/5)*y---> equation 2
B=(3/5)*y---> equation 3
B=R+24----> equation 4

substitute equation 2 in equation 1
[(2/5)*y]+B=y----> equation 5

substitute equation 2 in equation 4
B=[(2/5)*y]+24----> equation 6

resolve the system
[(2/5)*y]+B=y---> multiply by 5----> 2y+5B=5y----> 3y=5B
B=[(2/5)*y]+24----> multiply by 5----> 5B=2y+120

using a graph tool
see the attached figure

the solution is
B=72
y=120
R=y-B----> R=48

total marbies=x+y-----> 180+120-----> 300
tota; big marbies=180
percent of the marbles are big marbles
if 100%-----------> 300
 X----------------> 180
x=180*100/300-----> x=60%

the answer is
60%

so the perpendicular line goes through the given pointyou would get a perpendicular line at some random location

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.

A=l×wa=(8x+6) (13x+11)a=104x➋+166x+66