Simplify (sin2 θ + cos2 θ)(sin θ + cos θ) 1 2 sin θ + cos θ sin3 θ + cos3 θ

sin θ + cos θ

Explanation:
There is a trigonometric identity that states that:
sin²θ + cos²θ = 1

Now, for the given we have:
(sin²θ + cos²θ) (sin θ + cos θ)

Applying the above identity, we would find that the expression becomes:
(1) (sin θ + cos θ) which is equal to sin θ + cos θ

Hope this helps :)

The answer would be quadratic trinomial

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