Awheel with radius 1 foot makes 1 revolution in 4 seconds. what is the linear velocity, in feet per second, of a point on the edge of the wheel? pi/4 pi/2 4pi 8pi

Radius = r = 1 foot

Angular velocity = w = 1 revolutions in 4 seconds

So,

w = 0.25 revolutions per second

Since,

1 revolution = 2π radians

We can write the above equation as:

w = 0.25 x 2π radians per second = 0.5π radians per second

Linear Velocity = v = r w

Using the values, we can write:

v = 1 x 0.5π  

= 0.5 π

= π/2 feet per second

Therefore, the correct answer is option B

sure i'm up for it

step-by-step explanation: