You work in the packaging department of a company that makes soup. the old soup can is 4 inches high and has a diameter of 3 inches. your department is asked to design a bigger soup can that will hold one-and-a-half times as much soup as the old can. find the height of the bigger soup can if the diameter stays the same. the height of the new can will be in?

Step-by-step explanation:

step 1

Find the volume of the old can

The volume of the can is equal to

we have

----> the radius is half the diameter

substitute

step 2

Find the volume of the bigger can

Multiply the old volume by 1 1/2

so

step 3

Find the height of the bigger can

we have

substitute in the formula

1.5%

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.