What is the equation of the circle in general form? x2+y2−6x+10y+25=0 x2+y2+6x−10y+25=0 x2+y2−6x+10y+22=0 x2+y2+6x−10y+22=0?

By completing squares for all the equations we have:
 x2 + y2-6x + 10y + 25 = 0
 x2 + y2-6x + 10y = -25
 x2 + y2-6x + 10y + (- 6/2) ^ 2 + (10/2) ^ 2 = -25 + (- 6/2) ^ 2 + (10/2) ^ 2
 x2 + y2-6x + 10y + 9 + 25 = -25 + 9 + 25
 x2-6x + 9 + y2 + 10y + 25 = 9
 (x-3) ^ 2 + (y + 5) ^ 2 = 9

 x2 + y2 + 6x-10y + 25 = 0
 x2 + y2 + 6x-10y = -25
 x2 + y2 + 6x-10y + (6/2) ^ 2 + (- 10/2) ^ 2 = -25 + (6/2) ^ 2 + (- 10/2) ^ 2
 x2 + y2 + 6x-10y + 9 + 25 = -25 + 9 + 25
 x2 + 6x + 9 + y2-10y + 25 = 9
 (x + 3) ^ 2 + (y-5) ^ 2 = 9

 x2 + y2-6x + 10y + 22 = 0
 x2 + y2-6x + 10y = -22
 x2 + y2-6x + 10y + (- 6/2) ^ 2 + (10/2) ^ 2 = -22 + (- 6/2) ^ 2 + (10/2) ^ 2 
 x2 + y2-6x + 10y + 9 + 25 = -22 + 9 + 25
 x2-6x + 9 + y2 + 10y + 25 = 12
 (x-3) ^ 2 + (y + 5) ^ 2 = 12

 x2 + y2 + 6x-10y + 22 = 0
 x2 + y2 + 6x-10y = -22
 x2 + y2 + 6x-10y + (6/2) ^ 2 + (- 10/2) ^ 2 = -22 + (6/2) ^ 2 + (- 10/2) ^ 2
 x2 + y2 + 6x-10y + 9 + 25 = -22 + 9 + 25
 x2 + 6x + 9 + y2-10y + 25 = 12
 (x + 3) ^ 2 + (y-5) ^ 2 = 12