Tabitha wants to hang a painting in a gallery. the painting and frame must have an area of 58 square feet. the painting is 7 feet wide by 8 feet long. which quadratic equation can be used to determine the thickness of the frame, x? image of a frame 7 feet wide by 8 feet long, with an of x on the bottom and right sides x2 + 15x − 2 = 0 x2 + 15x + 58 = 0 4x2 + 30x − 2 = 0 4x2 + 30x + 58 = 0

therefore, the answer is

c. 4x2 + 30x − 2 = 0

if the total area of the painting and the frame is 58 sq ft, we have the equation:

(8 + 2x)(7 + 2x) = 58

expanding the equation,

56 + 30x + 4x^2 = 58

combining like terms and arranging the equation, we have:

4x^2 + 30x - 2 = 0

therefore, the answer is

c. 4x2 + 30x − 2 = 0

then, the surface area of the sphere shown in the image is: 256π sq. units!

step-by-step explanation:

the lateral surface area of a sphere is 2πrh where h=2r.

then:

surface area = 4πr^2.

in this case, r=8 units ⇒ surface area = 4π(8 units)^2. = 256π sq. units!

then, the surface area of the sphere shown in the image is: 256π sq. units!

3, 12, 48, 384, 1536, 6144, 24576, 98304

step-by-step explanation:

just keep timing it by 4.