The graph below shows a company's profit f(x), in dollars, depending on the price of erasers x, in dollars, being sold by the company: graph of quadratic function f of x having x-intercepts at ordered pairs 0, 0 and 8, 0. the vertex is at 4, 270part a: what do the x-intercepts and maximum value of the graph represent? what are the intervals where the function is increasing and decreasing, and what do they represent about the sale and profit? (6 points)part b: what is an approximate average rate of change of the graph from x = 1 to x = 4, and what does this rate represent? (4 points)this is the image, not sure if it will open though.

A. the x-intercepts represent break-even points, depending on the price of an eraser x. the maximum at (4, 270) means that maximum profit of 270 is received at the price of 4. this quadratic function is increasing from 0 to 4, and decreasing from 4 to 8. sales increase as the price is lowered, and the overall profit increases from 0 to 4 and decreases from 4 to 8.b. the equation of the parabola is y = a(x - 4)^2 + 270. substituting x = 0, y = 0 gives a = -135/8, so the equation is y = -135/8 (x - 4)^2 + 270. substituting x = 1 gives y = 118.125. then the average rate of change from x = 1 to x = 4 is: m = (y2 - y1) / (x2 - x1) = (270 - 118.125) / (4 - 1) = 50.625.this is the average rate at which profit increases as price is adjusted between $1 to $4/eraser.