For the function d(x)=7x^3 - 6x^2 what is the vaule of d(4)

For this case we have the following function:
 d (x) = 7x ^ 3 - 6x ^ 2
 We evaluate the function for x = 4.
 We have then:
 d (4) = 7 * (4) ^ 3 - 6 * (4) ^ 2
 Rewriting we have:
 d (4) = (4 ^ 2) * (7 * (4) - 6)
 d (4) = 352
 
 the vaule of d (4) is:
 d (4) = 352

Just tell koda to adjust the number of shapes himself.