The sum of three consecutive intergers is 36.if the first integer is y, find the value of y.

Hi,
Since they are consecutive, the equation will be:
y + (y + 1) + ( y + 2)=36
y + y + y +1 +2 = 36
3y + 3 = 36
3y = 36-3
3y = 33
y = 33/3
y=11
The three consecutive integers are 11, 12(11+1) and 13(11+2).
Hope this helps you.