Using cramer’s rule, what is the value of x in the system of linear equations below? 5x-4=3y 2x+32=4

What each term means:

Ax1 = X of the 1° equation coefficient.
Ax2 = X of the 2° equation coefficient.

By1 = Y of the 1° equation coefficient.
By2 = Y of the 2° equation coefficient.

C1 = Term Independent of the 1° equation.
C2 = Term Independent of the 2° equation.

1st Photo:

Here you have to adjust to the normal structure of a linear system (Normal structure in the 2nd photo).

2nd Photo:

Done, now you identify each term to calculate the determinants later.

3rd Photo:

This is the Cramer's Rule formula, which the N is the unknown term/variable/value, and the divisor Delta is the determinant of the coefficient of the variables (Ax1, By1....).

4th Photo:

Here you have to calculate the determinant of formed by the coefficients, and you find the Delta. To calculate a determinant you have to multiply the numbers diagonally.

Example: in the photo i calculated like this: 5 x 0, after this i calculated: (-3) x 2, when you multiply diagonally to the left (secondary diagonal) you invert the signal that you find. Done this now you have to sum the values that you found:
(5 x 0) + ((-3) x 2) = 0 + (-6) <- invert that signal
= 6

5th Photo:

Now you calculate the Delta X and Delta Y determinants, to do that you have to put, on the Delta X case, the independent terms in the place that you would put the X, and in the Delta Y case it's the same, put the independent terms in the place that you would put the Y.

After this, just substitute the values that you found in the formula:

Delta = 6 ; Delta X = -84 ; Delta Y = -148

1. 0.3 •4 is the same as 4 groups of 0.32. 7•0.8 is the same as 7 groups of 0.83. it increases by 0.5 every time, so 0.5x4 it increases by 0.9 every time, so 0.9x5. 0.9•12=10.86. 0.47•5=2.35i can finish the next ones in a separate post