Find the probability that a point chosen randomly inside the rectangle is in each given shape. round answers to the nearest hundreth. i need the percent.

9)    20.93%

10)  20%

11)   40.93%    

12)   59.07%    

We are given a rectangle of dimensions 10ft×6ft which inscribes:

Hence,

Here we have: r= 2ft.

Hence, Area of circle=(3.14)×(2)²

                                  = 12.56 square ft.

                                 =1/2×(4+2)×4

                                 = 12 square ft.

                                                = 10×6

                                                = 60 square ft.

Ques 9)

Probability that a point chosen lie on circle is:

  Area of circle/Area of rectangle

= 12.56/60

= 0.2093333

In percent it is given by: 20.93%

Ques 10)

Probability that a point chosen lie on trapezoid is:

  Area of trapezoid/Area of rectangle

= 12/60

= 0.2

In percent it is given by: 20%

Ques 11)

The circle or trapezoid is:

Probability that a point is chosen on circle+Probability that it is chosen on trapezoid.

= 40.93%

( Since,

P(A∪B)=P(A)+P(B)-P(A∩B)

and as circle and trapezoid do not have anything in common.

Hence, A∩B=∅

Hence, P(A∩B)=∅

Hence, P(A∪B)=P(A)+P(B)    )

Ques 12)

Not the circle and the trapezoid this means that the point will lie in the shaded region.

Hence, Probability is:

100%-Probability(it will lie either on circle or trapezoid)

=100%-40.93%

=59.07%

you need to show the graph

step-by-step explanation:

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet