The intensity of a radio signal from the radio station varies inversely as the square of the distance from the station. suppose intensity is 8000 units at a distance of 2 miles. what will the intensity be at a distance of 11 miles? round your answer to the nearest unit. a. 247 units b. 228 units c. 264 units d. 290 units

264 units

Explanation:
First, we will need to get the relation between the intensity and the distance.
We are given that the intensity varies inversely with the square of distance.
This means that:
Intensity = k / distance²
where k is the constant of proportionality.

We have:
intensity = 8000 at distance 2 miles
Therefore:
8000 = k / (2)²
k = 32000

Therefore, the relation now is:
intensity = 32000 / distance²

We want to get the intensity at distance 11 miles. Simply substitute in the above equation as follows:
intensity = 32000 / (11)²
intensity = 264.4 units which is approximately 264 units

Hope this helps :)

C.264 would be your answer