Cora is using successive approximations to estimate a positive solution to f(x)=g(x), where f(x)=x^2+13 and g(x)=3x+14. the table shows her results for different input values of x. x f(x) g(x) 0 13 14 1 14 17 2 17 20 3 22 23 4 29 26 3.5 25.25 24.5 use cora's process to find the positive solution, to the nearest tenth, of f(x)=g(x)

In the provided table it can be seen that for the values between 0 and 3    f (x) < g (x).  but from the x =4  f (x)> g (x)  for this to happen there must be a value between 3 and 4 where g (x) = f (x)  for x = 3.5 the difference decreases even more, but f (x) is still greater than  g (x). this indicates that the value of "x" must be greater than 3 and less than 3.5.  if we try with 3.3 we have:   f ( g (x)  3..89 23.9  the difference is 0.01. sufficient to say that f (x) = g (x) in x = 3.30