One leg of a 45 - 45 - 90 triangle measures 12 centimeters what is the length of the hypotenuse

The angles of the triangle are given as to have measures of 45°-45°-90°. This entails that the triangle is an isosceles triangle where the 2 legs of the triangle are of equal length. We calculate as follows:

c² = a² + b²

c² = 2a²

4² = 2a²

a = 2√2

Hope this answers the question.

Sin(a)+cos(a)+cot(a)-1=2(csc(x)+1)