Multiply the binomial and find the coefficients (x+y)^1=__×+__y (×+y)^2=__x^2+__xy+__y^2 (x+y)^3=__×^3+__×^2y+__y^3 (×+y)^4=__×^4+__x^3y+__x^2y^2+__xy^ 3+__y4

We can use the pascal triangle to solve this problem.
 
 For this case, rewriting each binomial we have:
 (x + y) ^ 1 = 1x + 1y

 (x + y) ^ 2 = 1x ^ 2 + 2xy + 1y ^ 2

 (x + y) ^ 3 = 1x ^ 3 + 3x ^ 2y + 3xy ^ 2 + 1y ^ 3

 (x + y) ^ 4 = 1x ^ 4 + 4x ^ 3y + 6x ^ 2y ^ 2 + 4xy ^ 3 + 1y4

I'm gonna have to say about 13 percent

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