Chaz is constructing the circumscribed circle for △jkl . which construction is a correct next step for chaz? open the compass to just more than half the width of jl¯¯¯¯¯ and draw a circle centered at point k. open the compass to the width of jl¯¯¯¯¯ and draw a circle centered at point k. construct the angle bisector of ∠j . construct the perpendicular bisector of jl¯¯¯¯¯ .

In order to construct a circle circumscribed to a triangle, you need to:
- first, find the perpendicular bisector of two of the sides of the triangle; 
- the two perpendicular bisectors will intersect in a point (C) that will be the center of the circle;
- point the compass in C and open it to the width of one of the points of the triangle (CJ or CK or CL);
- draw the circle.

Hence, the correct answer is: D) Construct the perpendicular bisector of JL.

Answer: 900°

good luck on your studies! : )

david edward.

A: 18/15b : 7 - -8 = 15 , 12 - -6 = 18 the y variable always goes over the x variables, c : same thing a