Giving away 50 points to whoever shows legit work! the lengths of the sides of three squares are s, s + 1, and s + 2. if their total area is 365 cm squared (^2), find their total perimeter.

S= one length of square 1
S+1 = one length square 2
S+2= one length square 3

Our equation would be
S^2+(S+1)^2+(S+2)^2=365

Idk if it would be called distribute but.. distribute
S^2+S^2+2S+1+S^2+4S+4=365

Add like terms
3S^2+6S-360=0

Divide everything. By 3
S^2+2S-120=0

Factor
(S-10)(S+12)=0

The two solutions are:

S-10=0
S=10

S+12=0
S=-12

Since a length can’t be a negative the only possible solution would be 10

Since a perimeter is all lengths added together we can multiply the length by four to get the perimeter

Square 1
10*4=40
Perimeter is 40cm

Square 2
S+1 =11
11*4=44
Perimeter is 44cm

Square 3
S+2=12
12*4=48
Perimeter is 48cm

Add all the perimeters together to get the total perimeter:

Total perimeter:
40+44+48=132

The total perimeter is 132cm

I hope this helps. Sorry if I messed up anything on here it was kinda hard to keep track of everything. Feel free to ask if you need anything cleared up :)

If jon had $4.00 then takes away $2.25, then he should have $1.75 left. $4.00 - $2.25 = $1.75 hope this ; )