Form a sequence that has two arithmetic means between 13 and 88. a. 13, 38, 63, 88 c. 13, 25, 25, 88 b. 13, 88, 163, 238 d. 13, 50.5, 88

The formula to use for this problem is this: an = a1 + (n - 1)d
Where:
a1 = 13
a4 = 88
n = 4
d = ?
Thus, we have:
88 = 13 + (4 - 1)d
88 - 13 = 3 * d
75 = 3d
75/3 = d = 25
Therefore, d = 25.
This means that, a difference of 25 exist between successive number in the sequence. So the right sequence is 13, 38, 63, 88.
The correct option is A.

Form a sequence that has two arithmetic means between 13 and 88.a.13, 38, 63, 88

It is blindness and randomization