A room has an area of square meters and a perimeter of 32 meters what are the length and width of the room

Width = 6 meters

Length = 10 meters

Explanation:

Here's the complete question:

A room has an area of 60 square meters and a perimeter of 32 meters. What are the length and width of the room?

Area = Length × Width

Perimeter = 2(Length + Width)

Therefore,

L × W = 60 i

2L + 2W = 32 ii

From equation ii,

2L + 2W = 32

Divide through by 2

L + W = 16

L = 16 - W iii

Put the value of L into equation i

L × W = 60

(16 - W) × W = 60

16W - W² = 60

W² - 16W + 60 = 0

W² - 10W - 6W + 60 = 0

W(W - 10) - 6(W - 10) = 0

(W - 6)(W - 10) = 0

Therefore,

W - 6 = 0

W = 0 + 6

W = 6

Width = 6 meters

Since Length = Area / Width

Length = 60/6

Length = 10 meters

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