A school stage has perimeter of 62 ft. and area 234 ft. find the dimensions of the school stage

W = 13, L = 18.

Explanation:

Given that Perimeter = 62ft and Area = 234ft

We have 2L + 2W = 62

2L = 62 - 2W

L = (62 - 2W) ÷ 2

L = 31 - W(i)

LW= 234(ii)

Substitute equation (i) from (ii)

(31 - W) W = 234

31W - W² - 234 = 0

-W² + 31W - 234 = 0

W² - 31W + 234 = 0

(W - 18) (W - 13) = 0

W - 18 = 0

Hence, we have W=18 , L=13

Or

W -13 =0

W = 13,  L = 18.

PROOF:

2 *18 + 2 * 13 = 62

36 + 39 = 62

62 = 62

And

13 * 18 = 234

234 = 234

Therefore, the final answer which is the dimensions of the school stage is Length 18ft and Width 13ft

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