In one day, a toy store sold 15 toy cars and 20 yo-yos for a total of $190. The next day, the toy store sold 3 toy cars and 12 yo-yos for a total of $102. What is the cost of one toy car?

Explanation:

Let the price of a toy car be a.

Let the price of a yo-yo be b.

You can solve this problem using simultaneous linear equation.

From the question above, you can form 2 separate equations.

For the first equation,

3 toy cars sold next day = 3a

12 yo-yos sold next day = 12b

Total price = $102

The second equation would be

Now, we are not finished yet. Make sure that for the first equation, only one of the unknown (a or b) stays on the left-hand side of the equation. Let's try a.

Lets move on with finding the second equation.

15 toy cars sold = 15a

20 yo-yos sold = 20b

Total price = $190

So, the second equation would be:

You don't have to move any unknowns to the other side for the second equation.

Now, take equation 1 and substitute into equation 2. This can be done by replacing the value of a in the second equation with the value of a on the right hand-side of the first equation. For example:

Hence, the price of a yo-yo, b, is $8. The price of a toy car is :

$2.

answer; the above statement is (false);

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2) yes, it could.