Three friends, Larry, Moe, and Curley, each begin the week with $20. The following table shows how much each of the friends spend on days 1-5 this week. LarryMoeCurley
DayMoney SpentDayMoney SpentDayMoney Spent
1$101$01$4
2$22$52$2
3$03$83$4
4$34$14$4
5$15$65$4
At the end of day 5, which of the three friends has the least amount of money?

The correct answer is Moe

Explanation:

The first step to know who spent less or more, and therefore who has the least amount of money by the end of day 5 is to find the total of money spent by each of the friends. This can be found by adding the money each person spent in the five days, which is shown by the table.

Larry= 10 + 2 + 0 + 3 + 1 = 16

Moe = 0 + 5 + 8 + 1 + 6 = 20

Curley = 4 + 2 + 4 + 4 + 4 = 18

Now, to find the money each person has by the end of day 5 it is necessary to  subtract the money spent from $20 (money at the end of the week)

Larry = $20 -  $16 =  $4

Moe= $20 - $20 = $0

Curley= $20 - $18 = $2

According to this, the person with the least amount of money by the end of day 5 is Moe because he has $0 left.

answer: this problem has only trivial solutions, with all points on the same line. x=5 or x=7/5.

step-by-step explanation:

there are three triangles, and three unknowns: x, y=length of middle segment, and z=cos(angles marked with red arc).

we need

and law of cosines,

the three equations are

see attached image for solution.

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