A 30.84 cm-3 volume of 0.128 M NaOH is required to reach the phenolphthalein endpoint in the titration of a 5.441g sample of vinegar .calculate the percent acetic acid in the vinegar.(Molar mass of vinegar is 60.05g/mol)

4.36%

Explanation:

Here is the complete question:

Calculate the percent acetic acid in vinegar when a 30.84cm^3 volume of 0.128 M NaOH is required to reach the phenolphthalein endpoint in the titration of a 5.441g sample of vinegar.(molar mass of vinegar is 60.05g/mol)

moles NaOH = 0.03084 dm^3 x 0.128

M=0.00395

mass acetic acid = 0.00395 mol x 60.05 g/mol=0.237 g

Percentage of acetic acid:

= 0.237 x 100/ 5.441

= 23.7/5.441

= 4.36%

false, the two are unrelated