For the triangle above, find sin A.
0.724
b. 49°
For the tizangle above, tina sina
a 07
50°
d. 0.69
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complete question:

For the triangle above, find sin A. a. 36° c. 0.9323 b. 50° d. 0.385

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d. 0.385

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Explanation:

The picture is represented below.  Using SOHCAHTOA principle sin A can be gotten below .

The triangle is a right angle triangle . It has the adjacent side, hypotenuse and the opposite side.

Sin A = opposite / hypotenuse

opposite side = 10

hypotenuse = 26

Sin A = opposite / hypotenuse

sin A = 10/26

sin A = 0.3846153846

sin A ≈ 0.385

simplify brackets

8 - 2a - 7 = a + 40

simplify 8 - 2a - 7 to -2a + 1

-2a + 1 = a + 40

add 2a to both sides

1 = a + 40 + 2a

simplify a + 40 + 2a to 3a + 40

1 = 3a + 40

subtract 40 from both sides

1 - 40 = 3a

simplify 1 - 40 o -39

-39 = 3a

divide both sides by 3

-39/3 = a

simplify 39/3 to 13

-13 = a

switch sides

a = -13