A10kg box initially at rest is pulled 18 meters accros horizontal, frictionless sutface by a 40 n what is the block's final velocity over the 18 meters?

Final Velocity = 144 m/s

Given that,

mass of the box = 10kg

distance the box travelled = 18m

initial speed = 0 m/s

Force = 40N

Force = mass x acceleration

40N = 10 x acceleration

acceleration = 40/10

acceleration = 4m/s²

where u = initial velocity

           v = final velocity

           a = acceleration

            s = distance

v - 0 = 2(4)(18)

v = 2(4)(18)

v = 144 m/s

So the block's final velocity = 144m/s

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