The specific heat of ice is 0.492 cal/ (g × °c). how many calories of heat are required to raise 100.0 g of ice from -20.0°c to -0.5°c?

For this case we have that the number of calories is given by the following equation:

C = mCpΔt

Where,

m: mass

Cp: specific heat

Δt : temperature differential

Substituting values we have:

Around 959.4 calories of heat are required to raise 100.0 g of ice from -20.0 ° c to -0.5 ° c

answer:

noting will happen take it easy ..

explanation:

don't be too much serious or worried nothing will happen to you .

drink a glass of water and maybe . just keep on roaming for a while so that the water is absorbed easily and don't forget to drink plenty of water .okk don't worry you will be fine

answer; /// i believe its the cochlea;