Wasp-32b orbits with a period of only 2.7 days a star with a mass that is 1.1 times that of the sun. how many au from the star is this planet? assume the orbital period of earth is 365 days.

To solve this problem we will use Kepler's third law of planetary motion. Formula for that law is:

Where:
T = orbital period
G = universal gravitational constant
M = mass of star
a = distance from planet to star

By rearranging this formula we get:

For Earth we have:

For Wasp-32b we have:
or
 

We can see that right sides are same. Left sides must be same. We can use this to solve for distance.



Wasp-32b is at distance of 0.038AU.

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