Acompound used to test for the presence of ozone in the stratosphere contains 96.2 percent thallium and 3.77 percent oxygen what is its empirical formula?

When ozone = O3. and we have 96.2% thallium of the compound. and 3.77% oxygen of the compound. We need to get the no.of moles of thallium & oxygen to get the empirical formula.
So we can assume that:
96.2% thallium = 96.2 grams of thallium
3.77% oxygen = 3.77 grams of oxygen
as each 100 gram of the compound contains 3.77 grams of O2 & 96.2 grams of Ti
no.of moles of thallium = 96.2 gm/molar mass of thallium 
                                       = 96.2 gm / 204 = 0.5 mol
no.of moles of oxygen = 3.77 gm / molar mass of oxygen 
                                      = 3.77 gm / 16
                                      = 0.25 mol 
to get the empirical formula we need to make this numbers a whole numbers so we multiply by 4 by oxygen and thallium to get the lowest whole numbers that we can get.
So, after multiple:
∴ no.of moles of oxygen = 1 
and no.of moles of thallium = 2 
So the empirical formula is 
Ti2O1 
→
Ti2O

Magma forms by partial melting of upper mantle and crust. partial melt means that only a fraction of the available material forms a melt, and that the remainder stays solid. the partial melt rises because of its lower density and ascends through he crust. this is so conclusive mean the answer would be magma igneous rocks or balistic magma.