What is the equation of the line that passes through the point (-6,6) and has a
slope of 1/3?

Explanation:

y-y = m(x - x)

I couldn't tell if the point was negative, so I'll do both

Positive                                      Negative

(6,6)  m= 1/3                             -(6,6)  m= 1/3

y-6 = 1/3(x - 6)                           y+6 = 1/3(x +6)

y-6 = 1/3x - 2                              y+6 = 1/3x + 2

y = 1/3x +4                                  y = 1/3x - 4