Given: EF is a diameter of the circle Find m∠EGF. A) 45° B) 60° C) 90° D) 100°

∠EGF = 90°

Explanation:

Question is incomplete as the attachment is missing.

To solve this I'll make an assumption that ∠EGF is an angle inscribed in the circle.

Given that

Line EF is a diameter;

Then the arc formed by EF is 180° (semi circle).

The inscribed angle theorem states that an angle θ inscribed in a circle is half of the central angle 2θ that subtends the same arc on the circle.

So, the inscribed angle

Arc EF = 2 * ∠EGF

Make ∠EGF the subject of formula

∠EGF = ½ EF

∠EGF = ½ * 180°

∠EGF = 90°