Proving the Third Corollary to the Inscribed Angle Theorem
Given: A circle with inscribed quadrilateral ABCD
Prove: ZA and ZC are supplementary.
1. Let mDCB = aº
Then mDAB =
360 - a 0.
А
VX
2. By the inscribed angle theorem, mzA=
a/
20
3. Also by the inscribed angle theorem, mZC = (360 -a)/2 .
В
360-a
2
4. Therefore, mZA+ m2C=
which simplifies tv
90
180
360
D
с
Check
Intro

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