What is the solution to the system of equations below?
3x + 4y = -2
2x – 4y = -8
A
B
x = 2, y = -2
x = 6, y = -5
Cx=
= 4, y = 4
D
x= -2, y = 1

x = -2, y = 1

Explanation:

Finding X:

3x + 4y = -2

2x - 4y = -8

      5x = -10

   5x/5 = -10/5

        x = -2

Why: Using the elimination method, you can eliminate 4y and -4y since they are opposites. Then its an addition problem; 3x plus 2x is 5x. -2 plus -8 is -10. From there it's "junk and divide"

Finding Y:

2(-2) - 4y = -8

    -4 -4y = -8

   +4          +4

        -4y = -4

    -4y/-4 = -4/-4

             y = 1    

Why: Because you found that x = -2, you can then plug it in one of the equations. From there its simple "junk and divide". Hope this helps this took a long time to type lol.    

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